A) Ethanal
B) Ethanol
C) Propyl amine
D) Acetic acid
Correct Answer: D
Solution :
Compound A is acetic acid. All the reactions are as follows: \[\underset{(A)}{\mathop{C{{H}_{3}}COOH}}\,\xrightarrow{N{{H}_{3}}}C{{H}_{3}}COON{{H}_{4}}\xrightarrow{\Delta }\] \[\underset{(B)\,Acetamide\,}{\mathop{C{{H}_{3}}CON{{H}_{2}}}}\,\xrightarrow[(dehydration)]{conc.\,{{H}_{2}}S{{O}_{4}}}\underset{(C)}{\mathop{C{{H}_{3}}CN}}\,\] \[\xrightarrow[\text{Reduction}]{Na/{{C}_{2}}{{H}_{5}}OH}\underset{\text{Ethyl}\,\,\text{amine}}{\mathop{C{{H}_{3}}C{{H}_{2}}N{{H}_{2}}}}\,\]
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