A) \[CC{{l}_{4}}\]
B) \[BC{{l}_{3}}\]
C) \[MgC{{l}_{2}}\]
D) \[NaCl\]
Correct Answer: B
Solution :
\[N{{H}_{3}}\] (ammonia) is a Lewis base (as it has a lone pair to donate), hence, it can form adduct with \[BaC{{l}_{3}}\] (a Lewis acid) by dative or co-ordinate bond. \[H--\underset{H}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{N}}}\,}}}\,:\xrightarrow{{}}\underset{Cl}{\overset{Cl}{\mathop{\underset{|}{\overset{|}{\mathop{B}}}\,}}}\,--Cl\]
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