A) 2448.45 kJ
B) 6528.2 KJ
C) 1632.3 kJ
D) 816.15 kJ
Correct Answer: C
Solution :
\[{{C}_{6}}{{H}_{6}}(l)+\frac{15}{2}{{O}_{2}}(g)\xrightarrow{{}}3{{H}_{2}}O(l)+6C{{O}_{2}};\,(9)\] \[\Delta H=-3264.6\,kJ\] \[6\times 12+6\times 1=78\] \[\because \] 78 g benzene, on heating gives = 3264.6 kJ energy \[\therefore \] 39 g benzene, on heating will give \[=\frac{3264.6\times 39}{78}=1632.3\,kJ\]You need to login to perform this action.
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