A) \[+1.36\,\,V\]
B) \[+\,2.71\,V\]
C) \[-\,2.03\,\,V\]
D) \[-\,2.71\,\,V\]
Correct Answer: B
Solution :
In the cell Mg will act as anode while Cu will act as cathode as the reduction potential of Mg is less Hence, \[E_{cell}^{\text{o}}=E_{cathode}^{\text{o}}-E_{anode}^{\text{o}}\] \[=\left( 0.34 \right)-\left( -\,2.37 \right)\] \[=0.34+2.37=2.71\,\,V\]You need to login to perform this action.
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