A) 6m
B) 4 m
C) 2m
D) 8 m
Correct Answer: D
Solution :
\[{{\upsilon }^{2}}={{u}^{2}}-2as\] (from equation of motion) \[s=\frac{{{u}^{2}}}{2a}=\frac{m{{u}^{2}}}{2am}=\frac{m{{u}^{2}}}{2F}\] \[s\propto {{u}^{2}}\] Hence \[\frac{{{s}_{1}}}{{{s}_{2}}}={{\left( \frac{{{u}_{1}}}{{{u}_{2}}} \right)}^{2}}\]or \[\frac{2}{{{s}_{2}}}=\frac{1}{4}\] \[{{s}_{2}}=8\,m\]
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