A) \[\frac{\sqrt{3c}}{2}\]
B) c
C) \[\frac{3c}{4}\]
D) \[\frac{c}{2}\]
Correct Answer: A
Solution :
Energy is given by the relation \[E=m{{c}^{2}}\] ?(i) \[E=2{{m}_{0}}{{c}^{2}}=\frac{2{{m}_{0}}}{\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}}\] ?(ii) By equation (i) and (ii), we get \[\sqrt{1-\frac{{{v}^{2}}}{{{c}^{2}}}}=\frac{1}{2},\] so, \[v=\frac{\sqrt{3}c}{2}\]
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