A) \[\text{3V}\]
B) \[\text{3/2V}\]
C) \[\text{2/3V}\]
D) \[\text{1/3V}\]
Correct Answer: C
Solution :
We know that the potential inside and on the surface of a spherical conductor is same so \[V={{V}_{surface}}=\frac{q}{10}\text{stat}\,\text{volt}\] \[{{V}_{out}}=\frac{q}{15}\text{stat}\,\text{volt}\] \[\frac{{{V}_{out}}}{V}=\frac{2}{3}\] so \[{{V}_{out}}=\frac{2}{3}V\]You need to login to perform this action.
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