A) \[\frac{f}{n}\]
B) \[nf\]
C) \[(n-1)f\]
D) \[(n+1)f\]
Correct Answer: D
Solution :
Magnifying power \[m=\frac{\upsilon }{u}=\frac{1}{n}\] or \[v=\frac{u}{n}\] here \[v\] is positive and \[u\] is negative \[\frac{1}{\upsilon }-\frac{1}{u}=\frac{1}{f}\] or \[\frac{n}{u}-\frac{1}{(-\,u)}=\frac{1}{f}\] so \[u=(n+1)f\]You need to login to perform this action.
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