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JIPMER Jipmer Medical Solved Paper-2001

  • question_answer
    If the gravitational force between two objects were proportional to\[\frac{1}{R}\](and not\[\frac{1}{{{R}^{2}}})\] where R is separation between then a particle in circular orbit under such a force would have its orbital speed \[\upsilon \] proportional to:

    A)  \[R\]         

    B)                         \[1/R\]                

    C)  \[R{}^\circ \]                    

    D)         \[1/{{R}^{2}}\]

    Correct Answer: C

    Solution :

    The force is given by \[F=\frac{{{E}_{k}}}{R}=\frac{m{{v}^{2}}}{2R}\] Hence   \[\upsilon \propto {{R}^{0}}\]


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