A) W
B) 4 W
C) 3 W
D) 2 W
Correct Answer: B
Solution :
From relation of work done \[W=\frac{1}{2}C{{V}^{2}},\] so \[W\propto {{V}^{2}}\] As \[{{V}_{2}}=60-30=30\,V,\] \[{{V}_{1}}=30-15=15\,V\] hence \[\frac{{{W}_{2}}}{{{W}_{1}}}={{\left( \frac{{{V}_{2}}}{V{{ & }_{1}}} \right)}^{2}}\] or \[{{W}_{2}}={{\left( \frac{30}{15} \right)}^{2}}W\] \[{{W}_{1}}=W\] \[{{W}_{2}}=4\,W\]You need to login to perform this action.
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