A) \[2Rg\]
B) \[Rg\]
C) \[\sqrt{Rg}\]
D) \[\sqrt{2Rg}\]
Correct Answer: D
Solution :
At infinity, potential energy of the particle is zero. When it approaches to earth, its potential energy\[=-\,mgR.\]. This difference in potential energy \[mgR=\frac{1}{2}m{{\upsilon }^{2}}\] So, \[\upsilon =\sqrt{2Rg}\]You need to login to perform this action.
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