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JIPMER Jipmer Medical Solved Paper-2002

  • question_answer
    One end of a copper rod of length 1.0 m and area of cross-section \[{{10}^{-3}}{{m}^{2}}\] is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is \[92\text{ }cal\text{/}m-s\text{ }{}^\circ C\] and the latent heat of ice is \[8\times {{10}^{4}}cal\text{/}kg,\] then the amount of ice which will melt in one minute is:

    A)  \[8\times {{10}^{-3}}kg\]      

    B)                         \[9.2\times {{10}^{-3}}kg\]        

    C)         \[5.4\times {{10}^{-3}}kg\]        

    D)         \[6.9\times {{10}^{-3}}kg\]

    Correct Answer: D

    Solution :

    From the formula\[\frac{d\theta }{dt}=mL\] where t = 1 m, m = mass, L = latent heat \[\frac{KA({{\theta }_{1}}-{{\theta }_{2}})t}{l}=mL\] \[m=\frac{KA({{\theta }_{1}}-{{\theta }_{2}})\times 60}{1\times 8\times {{10}^{4}}}\] \[m=\frac{{{10}^{-3}}\times 92\times (100-0)\times 60}{1\times 8\times {{10}^{4}}}\] \[=6.9\times {{10}^{-3}}kg\]


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