A) 2 s
B) 3 s
C) 1 s
D) 10.5 s
Correct Answer: C
Solution :
According to the question, if the length of the heater coil is reduced half, then the resistance also becomes half of the value \[\frac{{{E}^{2}}}{R}{{t}_{1}}=\frac{{{E}^{2}}}{R\text{/}2}{{t}_{2}},\] here\[{{t}_{1}}=2\,\,\sec \] therefore \[{{t}_{2}}=1\,\,\sec \]You need to login to perform this action.
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