A) \[\frac{(\upsilon -\upsilon )}{3\lambda }\]
B) \[\frac{3(\upsilon +\upsilon )}{\lambda }\]
C) \[\frac{(\upsilon +\upsilon )}{3\lambda }\]
D) \[\frac{3(\upsilon -\upsilon )}{\lambda }\]
Correct Answer: B
Solution :
We know that the relative velocity of sound waves with respect to the wall is given by \[\upsilon +\upsilon \] so, the apparent frequency of the waves striking. The surface of the wall is \[\frac{(\upsilon +\upsilon )}{\lambda }.\] Therefore, the number of positive crests striking per second is the same as frequency. So, in three seconds the number is \[\frac{(\upsilon +\upsilon )}{\lambda }.\] So, the number of positive crests striking per second is the same as frequency. In three seconds the number is\[\frac{3\,(\upsilon +\upsilon )}{\lambda }\].You need to login to perform this action.
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