A)
0.33 P
B) 0.44 P
C) 0.25 P
D) 0.5 P
Correct Answer: B
Solution :
The intensity I is inversely proportional to the square of the distance. Hence intensity\[I\]at\[Q\] \[{{I}_{1}}=\frac{P}{{{(d)}^{2}}}=\frac{P}{{{(2)}^{2}}}=\frac{P}{4}\] Intensity\[I\]at \[{{Q}_{1}},\] \[{{I}_{2}}=\frac{P}{{{(3)}^{2}}}=\frac{P}{9}\] So \[\frac{\text{Intensity}\,\text{at}\,Q\,({{I}_{1}})}{\text{Intensity}\,\text{at}\,{{Q}_{1}}({{I}_{2}})}=\frac{9}{4}\] Therefore, intensity at \[{{Q}_{1}}=\frac{4}{9}\] intensity at\[Q\].
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