A) Ohm = farad per second
B) Henry = ohm\[\times \]second
C) Henry = farad per second2
D) Farad = ohm per second
Correct Answer: B
Solution :
As farad\[=\frac{\text{coulomb}}{\text{volt}}\text{=}\frac{\text{ampere}\,\text{ }\!\!\times\!\!\text{ }\,\text{second}}{\text{volt}}\] \[\text{=}\,\,\frac{\text{second}}{\text{V/A}}\,\,\text{=}\,\,\frac{\text{second}}{\text{R}}\,\,\text{=}\,\,\text{second}\,\text{ohm}\] As the dimension of twice is \[\sqrt{LC}\] since, dimension of frequency is\[\frac{1}{\sqrt{LC}},\] so, \[\text{tim}{{\text{e}}^{\text{2}}}\] has the dimension of LC i.e., henry \[\times \] farad = \[\text{tim}{{\text{e}}^{\text{2}}}\]. Similarly henry/ohm has the dimension of time is correct.
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