A) trinitro glycerine
B) dynamite
C) glycerol trinitrate
D) none of these
Correct Answer: C
Solution :
Glycerol, with cone. \[HN{{O}_{3}}\] in cold, forms an ester i.e., glycerol trinitrate, which is used in making explosives, (like dyanamite, cordite etc.) \[\underset{Glycerol}{\overset{C{{H}_{2}}OH}{\mathop{\underset{C{{H}_{2}}OH}{\overset{|}{\mathop{\underset{|}{\mathop{CHOH}}\,}}}\,}}}\,+\underset{conc.\,Nitric\,acid}{\mathop{3HO\cdot N{{O}_{2}}}}\,\xrightarrow{conc.\,{{H}_{2}}S{{O}_{4}}}\]\[\underset{Glycerol\,trinitrate}{\overset{C{{H}_{2}}N{{O}_{2}}}{\mathop{\underset{C{{H}_{2}}ON{{O}_{2}}}{\overset{|}{\mathop{\underset{|}{\mathop{CHON{{O}_{2}}}}\,}}}\,}}}\,\]
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