A) \[N<O<F\]
B) \[F<O<N\]
C) \[N<F<O\]
D) \[O<N<F\]
Correct Answer: D
Solution :
The ionisation energy, in a period increases from left to right, hence, the increasing order should be N < O < F. But the actual order is O < N < F. The ionisation energy of nitrogen is greater than that of oxygen due to stabler electronic configuration of N (\[2{{p}^{3}},\]half-filled p-orbital).
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