A) \[1.05\times {{10}^{-28}}m\]
B) \[1.05\times {{10}^{-26}}m\]
C) \[5.27\times {{20}^{-30}}m\]
D) \[5.25\times {{10}^{-28}}\,m\]
Correct Answer: C
Solution :
According to Heisenbergs uncertainity principle \[\Delta x\cdot \Delta p=\frac{h}{4\pi }\] \[\therefore \] \[\Delta x=\frac{h}{4\pi \cdot \Delta p}\] \[=\frac{6.62\times {{10}^{-34}}\times 7}{4\times 22\times 1.0\times {{10}^{-5}}}\] \[=5.27\times {{10}^{-30}}m\]
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