question_answer

\[{{C}_{6}}{{H}_{5}}\cdot C{{H}_{3}}\xrightarrow[{{H}_{2}}S{{O}_{4}}]{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}Y,\]Here \[Y\]is:

A)  benzaldehyde                 

B)  toluene              

C)         benzoic acid    

D)         ethyl benzene

Correct Answer: C

Solution :

Toluene, gives different oxidation products, with different oxidizing agents. With \[Cr{{O}_{2}}C{{l}_{2}},\] it gives benzaldehyde, while with \[KMn{{O}_{4}}\text{/}{{H}^{+}}\] or \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\text{/}{{H}^{+}},\]it gives benzoic acid.