A) \[30.5{}^\circ C\]
B) \[37{}^\circ C\]
C) \[27{}^\circ C\]
D) \[29.3{}^\circ C\]
Correct Answer: D
Solution :
\[T=\frac{{{n}_{1}}{{C}_{{{\upsilon }_{1}}}}{{T}_{1}}+{{n}_{2}}{{C}_{{{\upsilon }_{2}}}}{{T}_{2}}}{{{n}_{1}}{{C}_{{{\upsilon }_{1}}}}+{{n}_{2}}{{C}_{{{\upsilon }_{2}}}}}\] \[=\frac{\frac{22}{14}\times 3R\times 300+\frac{16}{32}\times \frac{5}{2}R\times 310}{\frac{22}{14}\times 3R+\frac{16}{32}\times \frac{5}{2}R}\] \[=\frac{1414.3+387.5}{4.71+1.25}=302.3K=29.3{}^\circ C\]
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