A) (1 atmospheric pressure\[=1\times {{10}^{5}}N\text{/}{{m}^{2}}\]) \[2\times {{10}^{-8}}\text{J}\]
B) \[2\times {{10}^{-4}}\text{J}\]
C) \[\text{200J}\]
D) \[\text{2000J}\]
Correct Answer: B
Solution :
Work done is \[W=P\,\Delta \,V\] \[=2\times {{10}^{5}}\times (150-50)\times {{10}^{-3}}\] \[=2\times {{10}^{4}}J\]
You need to login to perform this action.
You will be redirected in
3 sec
