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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    Energy is being emitted from the surface of a black body at\[127{}^\circ C\]the rate of \[1.0\times {{10}^{-6}}\text{J/s}{{\text{m}}^{2}}.\] The temperature of black body at which the rate of energy emission is \[16.0\times {{10}^{-6}}\text{J/s}{{\text{m}}^{2}}\] will be:  

    A)  \[754{}^\circ C\]             

    B)         \[527{}^\circ C\]             

    C)         \[254{}^\circ C\]             

    D)         \[508{}^\circ C\]

    Correct Answer: B

    Solution :

    \[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\] \[\frac{{{T}_{2}}}{{{T}_{1}}}={{\left( \frac{{{E}_{2}}}{{{E}_{1}}} \right)}^{1/4}}={{\left[ \frac{1.6\times {{10}^{6}}}{1.0\times {{10}^{6}}} \right]}^{1/4}}=2\] \[{{T}_{2}}=2{{T}_{1}}=2\times {{T}_{1}}\] \[=2\times 400=800K=527{}^\circ C\]


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