A) \[9327{}^\circ C\]
B) \[1200{}^\circ C\]
C) \[927{}^\circ C\]
D) \[108{}^\circ C\]
Correct Answer: C
Solution :
\[{{T}_{1}}{{V}_{1}}^{\gamma -1}={{T}_{2}}{{V}_{2}}^{\gamma -1}\] \[{{T}_{2}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\gamma -1}}{{T}_{1}}\] \[{{T}_{2}}={{\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right)}^{\frac{5}{3}-1}}\times 300\] \[{{T}_{2}}={{\left( \frac{8}{1} \right)}^{2/3}}\times 300=4\times 300\] \[=1200K=927{}^\circ C\]
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