A) \[8\times {{10}^{6}}V\]
B) \[80\,V\]
C) \[9\times {{10}^{5}}V\]
D) \[9\,V\]
Correct Answer: A
Solution :
\[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\cdot \frac{Q}{R}=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{(Ze)}{R}\] \[=9\times {{10}^{9}}\times \frac{50\times 1.6\times {{10}^{-19}}}{9.0\times {{10}^{-15}}}\] \[=8\times {{10}^{6}}V\]
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