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JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    When a voltmeter connected across the terminals of cell, measures 5 V and an ammeter connected measures 10 A. A resistance of 2\[\Omega \] is connected across the terminal of the cell. The current flowing through this resistance is:

    A)  7.5 amp              

    B)         5.0 amp              

    C)         2.5 amp              

    D)         2.0 amp

    Correct Answer: D

    Solution :

    Internal resistance of the cell is \[r=\frac{E}{i}=\frac{5}{10}=0.5\,\Omega \] Current \[i=\frac{E}{R+r}=\frac{5}{2+0.5}=2\,amp\]


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