JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    If \[{{K}_{b}}\] of HCN is \[4.0\times {{10}^{-10}},\]then the pH of\[2.5\times {{10}^{-1}}\] molar aqueous HCN is:

    A)  2.0                                        

    B)  4.7                        

    C)  5.0                        

    D)         \[2\times {{10}^{-5}}\]

    Correct Answer: C

    Solution :

    \[[{{H}^{+}}]\]ln a solution of weak acid of cone. C and dissociation constant\[{{K}_{a}}\]is given as: \[[{{H}^{+}}]=\sqrt{{{K}_{a}}\times C}=\sqrt{4.0\times {{10}^{-10}}\times 2.5\times {{10}^{-1}}}\] \[=\sqrt{1\times {{10}^{-10}}}\] \[=1\times {{10}^{-5}}M\] \[pH=-\log \,[{{H}^{+}}]=-log{{10}^{-5}}=5\]


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