A) 0.0640 g
B) 0.0032 g
C) 0.0128 g
D) 0.0064 g
Correct Answer: D
Solution :
\[{{K}_{sp}}\]of \[Ca{{C}_{2}}{{O}_{4}}\] (a binary electrolyte) \[=2.5\times {{10}^{-9}}\] Now we know, \[{{K}_{sp}}={{S}^{2}}\] (S = molar solubility) or \[S=\sqrt{{{K}_{sp}}}=\sqrt{2.5\times {{10}^{-9}}}\] \[=5\times {{10}^{-5}}m{{L}^{-1}}\] Amount of \[Ca{{C}_{2}}{{O}_{4}}\]to make one litre saturated solution \[=5\times {{10}^{-5}}\,\text{moles}\times 128\,g\,\text{mo}{{\text{l}}^{-1}}\] \[=0.0064\text{ }g\]
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