JIPMER Jipmer Medical Solved Paper-2003

  • question_answer
    A ball falling in a lake depth 200 m shows a decrease of 0.1% in its volume at the bottom then the bulk modulus of the material of the ball is :                                           

    A)  \[19.6\times {{10}^{8}}\text{N/}{{\text{m}}^{\text{2}}}\]           

    B)  \[19.2\times {{10}^{7}}\text{N/}{{\text{m}}^{\text{2}}}\]

    C)                         \[2.4\times {{10}^{9}}\text{N/}{{\text{m}}^{\text{2}}}\]  

    D)         \[2.4\times {{10}^{5}}\text{N/}{{\text{m}}^{\text{2}}}\]

    Correct Answer: A

    Solution :

    \[K=\frac{\text{p}}{\text{Volume}\,\text{strain}}=\frac{hdg}{\text{Volume}\,\text{strain}}\]      \[=\frac{200\times {{10}^{3}}\times 9.8}{0.1\times {{10}^{-2}}}\]      \[=19.6\times {{10}^{8}}N\text{/}{{m}^{2}}\]


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