A) 0.66 A towards left
B) 0.66 A towards right
C) 1 A towards right
D) zero
Correct Answer: B
Solution :
Current due to both types of ions is in the same direction towards right so \[i={{i}_{1}}+{{i}_{2}}_{,}\] \[i=2.9\times {{10}^{18}}\times 1.6\times {{10}^{-19}}+1.2\times {{10}^{18}}\times 1.6\times {{10}^{-19}}\] \[i=0.66\,amp\]You need to login to perform this action.
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