A) \[12.5\times {{10}^{-2}}\text{J}\]
B) \[35\times {{10}^{-2}}\text{J}\]
C) \[42.5\times {{10}^{-2}}\text{J}\]
D) \[25\times {{10}^{-2}}\text{J}\]
Correct Answer: D
Solution :
When separation between the plates is doubled the capacitance becomes one half. It means \[C=25\mu F\] Now energy spent by the battery \[=qV=(CV)\,V\] \[=C{{V}^{2}}=25\times {{10}^{-6}}\times {{(100)}^{2}}\] \[=25\times {{10}^{-2}}J\]You need to login to perform this action.
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