A) 1 : 4
B) \[\frac{1}{4}:1\]
C) 2 : 1
D) 4 : 1
Correct Answer: D
Solution :
In a circular motion \[a=\frac{{{\upsilon }^{2}}}{r}\] \[\therefore \] \[\frac{{{a}_{2}}}{{{a}_{1}}}={{\left( \frac{{{\upsilon }_{2}}}{{{\upsilon }_{1}}} \right)}^{2}}={{\left( \frac{2{{\upsilon }_{1}}}{{{\upsilon }_{1}}} \right)}^{2}}=4\] \[\Rightarrow \] \[{{a}_{2}}:a{{ & }_{1}}=4:1\]You need to login to perform this action.
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