JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    The energy in MeV is released due to transformation of 1 kg mass completely into energy, is (\[c=3\times 10\text{ }m\text{/}s\]):

    A)  \[7.625\times 10\text{ }MeV\]

    B)  \[10.5\times {{10}^{29}}MeV\]

    C)         \[2.8\times {{10}^{-28}}MeV\]

    D)         \[5.625\times {{10}^{29}}MeV\]

    Correct Answer: D

    Solution :

    According to Einsteins mass energy equivalence \[E=m{{c}^{2}}=1\times {{(3\times {{10}^{8}})}^{2}}=9\times {{10}^{16}}J\]      \[=\frac{9\times {{10}^{16}}}{1.6\times {{10}^{-13}}}MeV\] (since \[1\,MeV=1.6\times {{10}^{-13}}J\]) \[=5.625\times {{10}^{29}}MeV\]


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