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JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    A charged particle is suspended in equilibrium in a uniform vertical electric field of intensity 20000 V/m. If mass of the particle is \[9.6\times {{10}^{-16}}~kg,\] the charge on it and excess number of electrons on the-particle are respectively \[(g=10\,\text{m/}{{\text{s}}^{\text{2}}}):\]

    A)  \[4.8\times {{10}^{-19}}C,\text{ }3\]      

    B)  \[5.8\times {{10}^{-19}}C,\text{ }4\]

    C)         \[3.8\times {{10}^{-19}}C,\,\,2\]              

    D)         \[2.8\times {{10}^{-19}}C,\text{ }1\]

    Correct Answer: A

    Solution :

    Charge on the particle is given by \[qE=mg\]           or            \[q=\frac{mg}{E}\] \[=\frac{9.6\,\times {{10}^{-16}}\,\times 10}{20000}\,=4.8\,\times {{10}^{-19}}\] When there is an excess of n electrons on the particle, then \[q=ne\] So,          \[n=\frac{q}{e}=\frac{4.8\times {{10}^{-19}}}{1.6\times {{10}^{-19}}}=3\]


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