JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    If the current 30 A flowing in the primary coil is made zero in 0.1 sec, the emf induced in the secondary coil is 1.5 volt. The mutual inductance between the coils is :

    A)  0.05H         

    B)                                        1.05 H                  

    C)         0.1 H                                    

    D)         0.2 H

    Correct Answer: A

    Solution :

    Here : \[e=1.5\,volt\] \[\Delta i=0-3=-\,3A,\]\[\Delta t=0.1\,\sec \] Now the emf induced in secondary coil \[e=\frac{M\Delta i}{\Delta t}(numerically)\] or            \[1.5=\frac{M\times 3}{0.1}\] or            \[M=\frac{1.5\times 0.1}{3}=0.05\,H\]


You need to login to perform this action.
You will be redirected in 3 sec spinner