A) \[2\times {{10}^{-5}}\text{Wb/}{{\text{m}}^{\text{2}}}\]
B) \[9\times {{10}^{-5}}\text{W/}{{\text{m}}^{\text{2}}}\]
C) \[4\times {{10}^{-5}}\text{W/}{{\text{m}}^{\text{2}}}\]
D) \[6\times {{10}^{-5}}\text{W/}{{\text{m}}^{\text{2}}}\]
Correct Answer: C
Solution :
Here : \[i=20A,\]\[r=10\,cm=0.1\,m\] Intensity of magnetic field produced due to straight current carrying wire is \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2i}{r}\] \[={{10}^{-7}}\times \frac{2\times 20}{0.1}\] \[=4\times {{10}^{-5}}Wb\text{/}{{m}^{2}}\]
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