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JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    When a resistance of a\[\Omega \]is connected at the ends of a battery, its potential difference decreases from 40 V to 30 V. The internal resistance of the battery is:

    A)  3 \[\Omega \]                                  

    B)         6\[\Omega \]                   

    C)         1.5 \[\Omega \]

    D)                                         4 \[\Omega \]

    Correct Answer: A

    Solution :

    \[E=40\,V,\]\[V=30\,V,\]\[r=a\,\Omega \] Internal resistance \[r=\left( \frac{E}{V}-1 \right)R=\left( \frac{40}{30}-1 \right)9\]    \[=\frac{1}{3}\times 9=3\,\Omega \]


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