A) Benzoic acid
B) Sodium benzoate
C) Benzaldehyde
D) Benzene
Correct Answer: D
Solution :
The reaction sequence is as follows: \[Ar{{N}_{2}}Cl\xrightarrow[Sandmeyers\,\,reaction]{CuCN/KCN}\] \[ArCN\xrightarrow{H.OH}\underset{benzoic\,\,acid}{\mathop{{{C}_{6}}{{H}_{5}}COOH}}\,\] \[\xrightarrow[decarboxylation]{\Delta ,\,sodalime}{{C}_{6}}{{H}_{6}}\]You need to login to perform this action.
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