A) 0.05H
B) 1.05 H
C) 0.1 H
D) 0.2 H
Correct Answer: A
Solution :
Here : \[e=1.5\,volt\] \[\Delta i=0-3=-\,3A,\]\[\Delta t=0.1\,\sec \] Now the emf induced in secondary coil \[e=\frac{M\Delta i}{\Delta t}(numerically)\] or \[1.5=\frac{M\times 3}{0.1}\] or \[M=\frac{1.5\times 0.1}{3}=0.05\,H\]You need to login to perform this action.
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