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JIPMER Jipmer Medical Solved Paper-2004

  • question_answer
    The \[Ka\] of an acid is \[3.2\times {{10}^{-5}}.\] The degree of   dissociation of the acid at concentration of 0.2 M is:

    A)  \[6.0\times {{10}^{-2}}\]                             

    B)  \[1.26\times {{10}^{-2}}\]           

    C)         \[40\times {{10}^{-4}}\]              

    D)         \[0.04\times {{10}^{-3}}\]

    Correct Answer: B

    Solution :

    From Ostwalds dilution law \[\alpha =\sqrt{\frac{Ka}{c}}\] \[=\sqrt{\frac{3.2\times {{10}^{-5}}}{0.2}}\] \[=1.26\times {{10}^{-2}}\]


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