A) 24.7 m
B) 19.8 m
C) 9.8 m
D) 4.9 m
Correct Answer: C
Solution :
Here: Initial velocity \[u=-\,4.9\,m\text{/}s\] (\[-ve\]is due to vertically upward motion) Total time \[t=2\,\sec \] The height of the bridge is given by \[s=ut+\frac{1}{2}g{{t}^{2}}\] \[=-\,4.9\times 2+\frac{1}{2}\times 9.8\times {{(2)}^{2}}\] \[=-\,9.8+19.6=9.8\,m\]You need to login to perform this action.
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