A) 0.1\[\Omega \]
B) 0.2\[\Omega \]
C) 0.3\[\Omega \]
D) 0.4\[\Omega \]
Correct Answer: A
Solution :
Here:\[{{I}_{g}}=0.01\,A,\]\[G=50\,\Omega \] To convert the galvanometer in to an ammeter of range 5A, a low resistance is to be connected in parallel with coil of galvanometer. \[S=\frac{{{i}_{g}}\times G}{i-{{i}_{g}}}\] \[=\frac{0.01\times 50}{5-0.01}=\frac{0.5}{4.99}=0.1\,\Omega \]You need to login to perform this action.
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