A) -3.8
B) -1.9
C) +3.8
D) +1.9
Correct Answer: D
Solution :
\[C(dia)+{{O}_{2}}\to C{{O}_{2}}\] \[(\Delta H=-395.4\,\,kJ\text{/}mole)\] ?(i) \[C(gr)+{{O}_{2}}\xrightarrow{{}}C{{O}_{2}}\] \[(\Delta H=-\,393.5\,kJ\text{/}mole)\] ?(2) subtracting eq. (i) from (ii), we have \[C(gr)\xrightarrow{{}}C(dia);\] \[(\Delta H=+\,1.9\,kJ\text{/}mole)\] \[[\because \,\Delta H=-\,393.5-(-395.4)=+1.9\,kJ\,mo{{l}^{-1}}]\]You need to login to perform this action.
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