A)
1.7
B) 1.4
C) 1.2
D) 2.7
Correct Answer: B
Solution :
From the formula, the minimum refractive index is \[{{\mu }_{m}}=\frac{\sin \,i}{\sin \,r}=\frac{\sin 90{}^\circ }{\sin \,45{}^\circ }\] \[=\frac{1}{1\text{/}\sqrt{2}}\] \[=\sqrt{2}=1.414\] \[\approx 1.4\]
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