JIPMER Jipmer Medical Solved Paper-2005

  • question_answer
    A prism of ten-active index \[\sqrt{2}\] has a refracting angle of\[60{}^\circ \]. At what angle a ray must be incident on it so that it suffers a minimum deviation:

    A) \[\text{4}{{\text{5}}^{\text{o}}}\]        

    B)                         \[{{60}^{\text{o}}}\]                     

    C)  \[{{90}^{\text{o}}}\]                     

    D)         \[{{180}^{\text{o}}}\]

    Correct Answer: A

    Solution :

    The relation for refractive index of prism is \[\mu =\frac{\sin i}{\sin r}\]                                        ?(1) The condition for minimum deviation is \[r=\frac{A}{2}=\frac{60{}^\circ }{2}=30{}^\circ \] Putting the given value of \[\mu =\sqrt{2}\] and \[r=30{}^\circ \] in eq. (1), we get \[\sqrt{2}=\frac{\sin i}{\sin 30{}^\circ }\] So,          \[\sin \,i=\sqrt{2}\times \frac{1}{2}=\frac{1}{\sqrt{2}}\] \[\sin i=\sin 45{}^\circ \]      \[i=45{}^\circ \]


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