A) \[Ni{{(CO)}_{4}}\]has oxidation number +4 for\[Ni\]
B) \[Ni{{(CO)}_{4}}\]has zero oxidation number for\[Ni\]
C) \[Ni\] is metal
D) \[CO\] is gas
Correct Answer: A
Solution :
In \[Ni{{(CO)}_{4}},\] carbonyl group is a neutral species. So oxidation number of Ni is zero. \[Ni{{(CO)}_{4}}\] \[x+4\times 0=0\] \[x=0\]
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