A) same
B) eight times
C) four times
D) twice
Correct Answer: C
Solution :
Increase in temperature of ideal gas from \[27{}^\circ C\] to \[927{}^\circ C\] \[\therefore \] Increase in \[KE=\frac{3}{2}RT\] \[{{T}_{1}}=27+273\Rightarrow 300\,K\] \[{{T}_{2}}=927+273\Rightarrow 1200\,K\] \[\therefore \] \[K{{E}_{1}}=\frac{3}{2}\times R\times 300\,K\] \[K{{E}_{2}}=\frac{3}{2}\times R\times 1200\,K\] So, \[\frac{K{{E}_{2}}}{K{{E}_{1}}}=\frac{\frac{3}{2}\times R\times 1200\,K}{\frac{3}{3}\times R\times 300\,K}=4\] Hence kinetic energy is increased four times.
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