A) 10, 6, 2
B) 11, 3, 7
C) 10, 3, 7
D) 10, 4, 7
Correct Answer: B
Solution :
Given \[O{{H}^{-}}\] ion cone. is \[{{10}^{-3}}M\] we know \[[{{H}^{+}}]\,[O{{H}^{-}}]={{10}^{-14}}\] or \[[{{H}^{+}}]\,=\frac{{{10}^{-14}}}{{{10}^{-3}}}\] or \[[{{H}^{+}}]\,={{10}^{-11}}\] \[\because \] \[PH=-\log [{{H}^{+}}]=-log[{{10}^{-11}}]\] Similarly pH of \[HCl\] is 3 and pH of \[NaCl\] is 7.
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