A) \[{{(Kg)}^{1/2}}\]
B) \[{{(Kg)}^{-1/2}}\]
C) \[{{(Kg)}^{2}}\]
D) \[{{(Kg)}^{-2}}\]
Correct Answer: A
Solution :
\[{{v}_{e}}=\sqrt{Rg}\] \[\frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{R}_{1}}}{{{R}_{2}}}\cdot \frac{{{g}_{1}}}{{{g}_{2}}}}\] \[=\sqrt{Kg}\] \[={{(Kg)}^{1/2}}\]You need to login to perform this action.
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