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JIPMER Jipmer Medical Solved Paper-2006

  • question_answer
    The equation of stationary wave along a stretched string is given by \[y=5\,\sin \frac{\pi x}{3}\cos \,40\,\pi t,\] where, x and y are in cm and r in second. The separation between two adjacent nodes is:

    A) 1. 5 cm 

    B)                                        3 cm

    C) 6 cm                      

    D)        4 cm

    Correct Answer: B

    Solution :

    Given, equation \[y=5\sin \frac{\pi x}{3}\cos 40\pi t\] Comparing with standard equation \[y=A\sin kx\cos \omega t\] \[\therefore \]  \[k=\frac{\pi }{3}\] \[\Rightarrow \]               \[\frac{2\pi }{\lambda }=\frac{\pi }{3}\] \[\lambda =6\,cm\] Separation between two consecutive nodes \[=\frac{\lambda }{2}=\frac{6}{2}=3\,cm.\]


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